ファイル名を入れるだけで自動でリンクを作りたい

def getHeaderYaml(path):
    """
    mdのヘッダーに書かれているYaml形式のメタデータをDictで取得する
    """

    with codecs.open(path, "r", 'utf-8') as f:
        lines = f.readlines()

    flg = False

    retVal = []

    for i in lines:
        if flg and i.strip() == "---":
            # 最後の ---
            break
        elif not flg and i.strip() == "---":
            # 最初の ---
            flg = True
        else:
            retVal.append(i)

    if len(retVal):
        return yaml.safe_load("".join(retVal))
    return None


def searchMarkdownFile(fileName, word=""):

    for root, dirs, files in os.walk(os.path.join(os.getcwd(), 'docs')):
        for f in files:
            bn, ext = os.path.splitext(f)
            if ext == ".md" and bn == fileName:
                path = os.path.join(root, f)
                header = getHeaderYaml(path)
                buff = root.replace("\\", "/").split("/docs/")
                linkPath = f"/reincarnation_tech/{buff[-1]}/{bn}"
                linkText = word if word != "" else header['title']
                return f":fa-external-link: [{linkText}]({linkPath})"
    return ""

def define_env(env):

    @env.macro
    def markdown_link(filename, word=""):
        return searchMarkdownFile(filename, word)